Question

Find the solution of the logarithmic equation logbase(2)(x^2-4x-28)=2

Answer 1

\[\log _{2}(x^2-4x-28)=2\]

Answer 2

take 2^ both sides

Answer 3

what do you mean?

Answer 4

\[\Large 2^{\log _{2}(x^2-4x-28)}=2^2\]

Answer 5

on the left "2 to the power of" cancels logbase2...

\[x^2-4x-28=4\]

Answer 6

okay, so I need to factor correct?

Answer 7

yes

Answer 8

okay so (x+4) (x-8) = 0?

Answer 9

right.

x=-4 or x=8

both answers work if you plug in the original equation.