f(x) = 19xe^(1 − x^2)
what do you need to do...?
Find the exact location of all the relative and absolute extrema of the function.
well perhaps you should graph it 1st here is a sight I use https://www.desmos.com/calculator then you can see them... makes the calculus a little easier
i did that and i typed in what i got and it came out wrong>.<
type in y = 19xe^(1 - x^2) and it should work
the graphing works! but the point are wrong when i put them as my answer!
is there a domain in your question..?
nope
f(x) = x4 − 8x3 with domain [−1, +∞) do you know how to do this one?
f(x)=x^4 - 8x^3 domain -1,+infinity
f(x) = x^4 - 8x^3 f'(x) = 4x^3 - 24x^2 = 4x^2(x - 6) = 0 x = 0, x = 6 are critical points. f''(x) = 12x^2 - 48x f''(0) = 0 (therefore x = 0 is not a local maxima / minima_ f''(6) = 12*36 - 48*6 = 144. f''(6) > 0, therefore x = 6 is a local minima.
so what is the y?
im so lost and my homework is due at 10 am:/
at x = 6, f(6) = 6^4 - 8*6^3 = -432.
So when x = 6, the corresponding y value is -432.
so its telling me that its wrong>.<
wait just kidding it took it!
f(x) = x ln x with domain (0, +∞) do you know how to do this one by chance?
domain (0,+infinity)
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