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Calculus1 23 Online
OpenStudy (aliaaalihassan):

ln2x=4 solve for x

OpenStudy (anonymous):

it is 2

OpenStudy (anonymous):

tell her how to find the answer @victoriajustice

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

2

OpenStudy (anonymous):

i divided 4/2 because it multiplication and you get the answer2

OpenStudy (aliaaalihassan):

Its actually not that cute simple my question is LN2x=4 Ln" log e"

OpenStudy (gorv):

\[\log_{a} b=c\] can be written as \[b=a^c\]

OpenStudy (gorv):

a=base and ln has base=e

OpenStudy (anonymous):

what

OpenStudy (anonymous):

do you want me to help you

OpenStudy (anonymous):

@victoriajustice you ignored the ln by simply dividing by 2

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

Look at gorv's explanation above.

OpenStudy (anonymous):

do we need to multiply

OpenStudy (anonymous):

Don't worry about it, this math is probably a little higher than what you've taken. You will learn it eventually in pre-calc.

OpenStudy (anonymous):

doe that mean pre -calculus

OpenStudy (aliaaalihassan):

Still you guys can anybody solve it

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

just give us a minute

OpenStudy (anonymous):

ln2x is just \[\log_{e} {2x} =4\]

OpenStudy (anonymous):

@AliaaAliHassan again look at gorv's explanation he basically told you the answer.

OpenStudy (anonymous):

\[e ^{4}\]=2x

OpenStudy (anonymous):

x=e^4/2

OpenStudy (anonymous):

i thought it was x=1/2 e to the power of 4

OpenStudy (aliaaalihassan):

can you help me guys with this also e^x(x^2-1)=0

OpenStudy (anonymous):

do you have to sole for x

OpenStudy (anonymous):

cause if you do it would be 1,-1

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