Calculus1
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OpenStudy (aliaaalihassan):
ln2x=4 solve for x
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OpenStudy (anonymous):
it is 2
OpenStudy (anonymous):
tell her how to find the answer @victoriajustice
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
2
OpenStudy (anonymous):
i divided 4/2 because it multiplication and you get the answer2
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OpenStudy (aliaaalihassan):
Its actually not that cute simple my question is LN2x=4 Ln" log e"
OpenStudy (gorv):
\[\log_{a} b=c\]
can be written as
\[b=a^c\]
OpenStudy (gorv):
a=base
and ln has base=e
OpenStudy (anonymous):
what
OpenStudy (anonymous):
do you want me to help you
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OpenStudy (anonymous):
@victoriajustice you ignored the ln by simply dividing by 2
OpenStudy (anonymous):
oh
OpenStudy (anonymous):
Look at gorv's explanation above.
OpenStudy (anonymous):
do we need to multiply
OpenStudy (anonymous):
Don't worry about it, this math is probably a little higher than what you've taken. You will learn it eventually in pre-calc.
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OpenStudy (anonymous):
doe that mean pre -calculus
OpenStudy (aliaaalihassan):
Still you guys can anybody solve it
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
just give us a minute
OpenStudy (anonymous):
ln2x is just \[\log_{e} {2x} =4\]
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OpenStudy (anonymous):
@AliaaAliHassan again look at gorv's explanation he basically told you the answer.
OpenStudy (anonymous):
\[e ^{4}\]=2x
OpenStudy (anonymous):
x=e^4/2
OpenStudy (anonymous):
i thought it was x=1/2 e to the power of 4
OpenStudy (aliaaalihassan):
can you help me guys with this also e^x(x^2-1)=0
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OpenStudy (anonymous):
do you have to sole for x
OpenStudy (anonymous):
cause if you do it would be 1,-1