Question

Calculate the pH of solution prepared by Mixing equal volumes of 0.20M HCl and 0.50 M HNO3 (Assume that volumes are additive)

Answer 1

they are two strong acids, then the pH is going to be given by the total concentration of the H given by both acids.
You can assume that the volumes that you mix is one liter of each acid and you will have a final volume of 2 liters.
If you put one liter of HCl acid 0.20M you will have a total of 0.2 moles of H+
If you put one liter of HNO3 acid 0.50M you will have a total of 0.5 moles of H+
now your total moles of H+ will be 0.2+0.5=0.7
you have that moles in 2 liters of final volume, then the concentration will be 0.7/2
with the [H+] concentration you can calculate the pH = -log [H+]

Answer 2

i did the exact calculation, but im not getting the answer thats in the back of my book. so i was confused.

Answer 3

the answer in the back saids 2.92

Answer 4

Something else must be wrong. So far I know and checked several places I would said the pH will be = 0.456

https://www.youtube.com/watch?v=FQxozHiv4sI

Answer 5

i guess the answer in the back of the book is wrong. I looked at the same video you showed me before i asked this question :P Thanks for helping out