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Determine the equation of the axis of symmetry of the parabola with points (-5,3) and (3,3) equally distant from the vertex on either side of it.
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Find the x-coordinate of the midpoint. The axis will be a vertical line passing through the midpoint.
y= a(x-r) (x-s)
So we have to used this formula
What is the midpoint of (-5,3) and (3,3) ?
1
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5-3 divide by 2
midpoint = ( (x1+x2)/2, (y1+y2)/2 )
what is that?
( (x1+x2)/2, (y1+y2)/2 )
Midpoint = \(\Large\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} \right) \) x-coordinate of midpoint = (-5+3)/2 = -2/2 = -1 x = -1 is the axis of symmtery.
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oh ok
thanks buddy
yw.
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