Fm=Fc question regarding graphs
if the speed of an electron increases then does the radius of its curved path also increase?
looking like this?|dw:1414194628570:dw|
the electron is moving in a magnetic field? or somewhere else ?
magnetic!
if u consider it moving in a magnetic field then it will feel two kind of forces - \[(1) centripetal ~force\\(2)lorentz~force\] and they will balance each other to establish equilibrium-- centripetal force on the electron will be due to circular motion \[F_{centripetal}=\frac{ mv^2 }{ r }\\where\\v=velocity ~of ~the ~electron\\r=radius ~of ~the~path\] and the lorentz force will be-- \[F_{lorentz}=Q*(BXv)=QBv\\Q=charge\\B=magnetic field ~flux\\v=velocity\] so for equilibrium-- \[F_{centripetal}=F_{lorentz}\\ \frac{ mv^2 }{ r }=QBv\\mv=QBr\\so ~we~can~see~r~(radius ~of ~the~path)~~is proportional ~with~the ~velocity\]so graph will look like |dw:1414219765714:dw|
got this?
ok so what you said "we can see r......... with velocity" could you explain what you did with the formula and why it would be proportional?
look the final expression we got is \[mv=QBr\] right?
so from here \[v=\frac{ QBr }{ m }=(\frac{ QB }{ m})r=K*r\\where~~K= A~~constant ,\]
so from here cant we say that v is proportional to r ?
oh ok ok thnks
np :)
OH WAIT @sidsiddhartha
my friend said that |dw:1414220801957:dw|
it can also be this but that means its not directly proportional though
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