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5y2+3y-2;y=-1
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Where does the multiplication go
MAybe 5(y)(2)+3y-2
I haven't solved it yet, I need help. It's from my book
10y+3y-2 13y-2 13(-1)-2-= -13-2= -15
what I got for the 5y^2 part was 125 is that not right?
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No, it is not. You are forgetting your order of operations. Remember BEDMAS (Brackets, Exponentiation, Division, Multiplication, Addition, Subtraction). In 5*y^2, the first thing you should do is find y^2 and then multiply by 5.
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