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Mathematics 16 Online
OpenStudy (anonymous):

5y2+3y-2;y=-1

OpenStudy (anonymous):

Where does the multiplication go

OpenStudy (anonymous):

MAybe 5(y)(2)+3y-2

OpenStudy (anonymous):

I haven't solved it yet, I need help. It's from my book

OpenStudy (anonymous):

10y+3y-2 13y-2 13(-1)-2-= -13-2= -15

OpenStudy (anonymous):

what I got for the 5y^2 part was 125 is that not right?

OpenStudy (carson889):

No, it is not. You are forgetting your order of operations. Remember BEDMAS (Brackets, Exponentiation, Division, Multiplication, Addition, Subtraction). In 5*y^2, the first thing you should do is find y^2 and then multiply by 5.

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