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Mathematics 13 Online
OpenStudy (anonymous):

cos(2theta-pi/2=-1

OpenStudy (shinalcantara):

OpenStudy (shinalcantara):

remember that cosine is -1 in the negative x-axis

OpenStudy (mathmath333):

is it this ? \(\large\tt \begin{align} \color{black}{cos(2\theta-\dfrac{\pi}{2})=-1}\end{align}\)

OpenStudy (shinalcantara):

@mathmath333 try to check the answer you'll end up with cosine zero which is '1'

OpenStudy (mathmath333):

i dont know u can show ur work and correct my answer

OpenStudy (shinalcantara):

\[\cos (2\theta - \frac{ \pi }{ 2 }) = -1\] using the difference of the cosine of two angles cos(A-B)=cosAcosB+sinAsinB you'll have: \[\cos2 \theta \cos \frac{ \pi }{ 2 } + \sin2 \theta \sin \frac{ \pi }{ 2 } = -1\] cosine pi/2 or 90degrees is zero. it will be cancelled out sin pi/2 = 1 \[\sin 2 \theta = -1\] \[2 \theta = \sin^{-1} (-1)\] remember that when sine is -1, it lies in 270degrees or 3pi/2 \[2 \theta = \frac{ 3 \pi }{ 2 }\] \[\theta = \frac{ 3 \pi }{ 2(2) }\] \[\theta = \frac{ 3 }{ 4 } \pi\]

OpenStudy (shinalcantara):

@cc1125 please refer to the unit circle i attached above

OpenStudy (mathmath333):

oh i think ur method is optimum and correct here

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