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expand (sin(x))^6 in the form of cos(x)
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Write it like \[\sin(x)=\frac{ e ^{x}-e ^{-x} }{ 2i }\] and simplify.
I think we can use the trig identity: \( \sin^2 x + \cos^2 x = 1 \) here to get a form of cosine. \( \sin^2 x = 1 - \cos^2 x \) Just rewrite: \( \sin ^6 x = \left( \sin ^2 x \right)^3 \) using the exponent property, and then apply the identity. Expand the resulting binomial cubed.
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