Question

e^(x+6)=(e^x)+6

Answer 1

Ooo that 6 sure is sneaky, huh?

Answer 2

hmm

Answer 3

\[\Large\rm e^{x+6}=e^x\cdot e^6\]There our problem:\[\Large\rm e^{x+6}=e^x+6\]Can be written as:\[\Large\rm e^x\cdot e^6=e^x+6\]\[\Large\rm e^x\cdot e^6-e^x=6\]\[\Large\rm e^x(e^6-1)=6\]

Answer 4

\[\Large\rm e^x=\frac{6}{e^6-1}\]Then we can use a log to get the x out of the exponent position, yah?

Answer 5

`There our problem`? That was a weird typo lol

Answer 6

not sure how to do that @zepdrix

Answer 7

i also got up to the part that you did but got stuck after

Answer 8

\(\large\tt \begin{align} \color{black}{ e^x=\frac{6}{e^6-1}\\~\\
\ln e^x=\ln (\frac{6}{e^6-1})\\~\\
x\ln e=\ln (\frac{6}{e^6-1})\\~\\
x=\ln (\frac{6}{e^6-1})-----(use~~e=2.718)\\~\\
x=\ln(0.0149.....)\\~\\
x=-4.2}\end{align}\)

Answer 9

thank you so much