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Mathematics 21 Online
OpenStudy (anonymous):

what are the roots of the function y=x^3+4x^2+3x=0

OpenStudy (anonymous):

OpenStudy (anonymous):

First test some x values so see which one will give y = 0. After some testing we can see y = 0 when x = -1 When x = -1, y = 0 So therefore, (x+1) is a factor of the function Next we factorise the function through synthetic division x^3+4x^2+3x=(x+1)(x^2+3x) I'm sure you can find the roots now

OpenStudy (anonymous):

i'm confused :(

OpenStudy (campbell_st):

just look at the graph you posted, the roots are the x -intercepts for the curve. x = 0, -1 and you can work out the last 1

OpenStudy (anonymous):

-3 ??? @campbell_st

OpenStudy (campbell_st):

that's correct

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