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Chemistry 12 Online
OpenStudy (anonymous):

Calculate the number of moles in each sample. 69.7 g HCCl3

OpenStudy (anonymous):

@Technodynamic

OpenStudy (anonymous):

@CO_oLBoY

OpenStudy (anonymous):

Do you know how to answer this?

OpenStudy (technodynamic):

\[69.7 g HCCl3 * \frac{ mol HCCl3 }{ 119.37 g HCCl3 } = 0.584 mol HCCl3\]

OpenStudy (anonymous):

could you please explain how you set up that problem?

OpenStudy (anonymous):

the thing is i have three more of these questions and i wanna learn how to do them

OpenStudy (technodynamic):

step 1: start w/ the grams given. step 2: they ask how many moles, so you add every element in HCCl3 For example: Look at the periodic table. Hydrogen = 1.008 g , Carbon = 12.01 g Cl = 35.45 g. In Cl there are 3 of them so you multiply 35.35 * 3. How to do it: Add up all of them. Example: H: 1.008 C: 12.01 Cl: 35.45 *3 = Total of all of them 119.37 g/ mol step 3: you set it up in dimensional analysis to where grams cancels to leave only moles. step 4: divide

OpenStudy (anonymous):

okay i got it. thank you very much!

OpenStudy (technodynamic):

it'll be hard at first, but you got this. i have faith! You're welcome! :)

OpenStudy (anonymous):

thank you :)

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