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Calculus help
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\[\int\limits_{}^{} x^2\sqrt{1+x^3}dx\]
You'll need to do a little u-substitution here :)
HINT: Take \((1+x^3) = u\)
i solved the problem and i got \[\frac{ 2 }{ 9 }(1+x^3)^\frac{ 2 }{ 3 }+C\]
No, it'd be \[\Large \frac{ 2 }{ 9 }\sqrt{1+x^3}^\frac{ 3 }{ 2 }+C\]
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ah yes i typed it in wrong it was 3/2 as the exponent
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