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I need help with systems of equations...
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use substitution or elimination (and there are other methods for order three and higher)
Its 3 x-2y+2z=8 3x+y-z=3 -x-3y+2z=6
I have no idea how to solve any of it...
First add 1st and 3rd to get a relation in y and z. Then use any two to eliminate x. Then solve for y and z.
So add x-2y+2z=8 and -x-3y+2z=6?
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Yes :)
So is it -5y+4z=14 or is it y+4z=14?
|dw:1414352617206:dw|
The first one is right :)
Okay thats what I got then what do I do from there?
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So now for a second relation, multiply equation no 3rd by 3. Then add the eqn 2nd and 3rd
What????
|dw:1414352727313:dw|
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