A mole of hydrogen atoms with their electron in the n = 6 energy level emit 109.4 kJ of energy. In what energy level (n) does the electron end up?

Question

cuanchi · Answer

$$Delta E=-2.18 \times 10^{-18}J(\frac{ 1 }{ n _{f}^{2} }-\frac{ 1 }{ n _{i}^{2} })$$

anonymous · Answer

thanks for the formula but what does n^2 f mean

cuanchi · Answer

that is the value that you have to calculate is the final level where the electron felt.

anonymous · Answer

oh okay so i know my energy and my final but am solving for the inital?

anonymous · Answer

or is n=6 my initial.. I'm not sure?

cuanchi · Answer

yes n=6 is your initial and you have to find your final. But the formula is for the energy of a single electron, and in your problem you have a mol of electron so you have to divide that energy by the Avogadro's number

cuanchi · Answer

Besides that energy is in kJ and in the formula the constant is in Joules