What is the mass (in grams) of 9.44 × 1024 molecules of methanol (CH3OH)?

Question

anonymous · Answer

1.) Remember this
    
 Grams-Moles-Atoms, our goal is to get mass in this problem


2.) Find moles, So we start at Atoms and convert all the way to Moles


      9.44*10^24Atoms CH3OH * 1mole
                                                6.022810^23atoms <-- Avogardo constant
       CH3OHmoles=15.6758


4.) Find mass, we have moles, so now we can calculate mass
      
CH3OH 15.6758mole  * 32.0419grams<-- mass of CH3OH
                                     1mole
  CH3OH mass= 502.28grams