Find an equation of the line parallel to 6x + 2y = 49 containing the point (4,9).
geometry or algebra1?
Give me a point that is related to 4,9 such as...6,11 or something..
adv algebra
how about (6,110! lol @SexyBeast890
My fault o.o It was 6,2 not 6,9 o.o Any who all we gotta do is change the =... So we keep: 6x + 2y But change: =49 = 56 so our equation will now look like 6x + 2y = 56
So how would I write that in slope intercept form?
since the lines are parallel, the slope will be the same. you also know one point on the line (4,9). then you plug these values into the line equation y=m(x-x1) + y1 where x1=4, y1=9 and m=slope=6
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6x+2y=49 first find the slope of this equation
So what would the equation be in slope form?
point-slope or slope-intercept?
slope-int
subtract 6x from both sides then divide by 2y right?
ok. remember slope-intercept is y=mx+b where m is slope and b is your y-intercept
that way you have it in y = mx + b
so 6x+2y=49 is in standard form, Ax +By=C and to find the slope, its -A/B so the slope is -6/2= -3
so you know m=-3 and (x,y)= (4,9) plug it in 9=-3(4)+b 9= -12+b +12 +12 ---------- 21=b so you're slope inter form is y=-3x+31
i meant y=-3x+21
So 6x + 2y =49 as a parallel line containing the point (4,9) is y=-3x + 21?
yes
y=-3x+21 is the equation of the line that contains (4,9) and is parallel to 6x+2y=49
THANKS! THIS MAKES SO MUCH MORE SENSE NOW!
you're welcome!
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