Question

Calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from n = 7 to n = 1.

Answer 1

\[E=-2.18\times10^{-18}J(\frac{ 1 }{n _{f}^{2} }-\frac{ 1 }{ n _{i}^{2} })\]
ni= initial state
nf= final state