Question

g(x)=5x+9/2x^2+93
Find domain of g

Answer 1

The domain is all the values x can be. The only thing that cannot happen to this function is the denominator (numbers bellow/to the right of the division sign) equaling 0, because then it would be undefined. So you need to find the value(s) of x for when the denominator equals 0.

Answer 2

how do i do that?

Answer 3

?

Answer 4

2x^2+93=0
Solve for x.
Hint: if possible factor it out.

Answer 5

Sorry, my internet is slow.

Answer 6

The answers you get means the domain is all numbers except for (the answers you get for x). Get it?

Answer 7

okay that makes sense. how do i factor that? I'm bad at factoring unless its ax^2+bx+c

Answer 8

Yeah, that's way too complicated to factor this out. Just do it the regular way.

Answer 9

regular way?

Answer 10

Just solve for x, haha. :)

Answer 11

Y'know, this whole thing
2x^2+93=0
-93 -93
------------
2x^2=-93
Now do the rest.

Answer 12

but then I get a decimal ha. I can't use decimals. I have no idea how to square root a fraction??

Answer 13

Then just leave it as a square root. remember it's plus or minus square root.

Answer 14

2x^2=-93
/2 /2
---------
x^2 = -46.5
sqrt sqrt
\[x=\pm \sqrt{-46.5}\]
\[x=\pm i \sqrt{46.5}\]

Answer 15

Get it? Okay, it is late and I'm tired. Sorry I have to abruptly leave... If you don't get it, you can tag someone else. It's just I am seriously so tired. Good nigh! :)