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OpenStudy (anonymous):

If an object undergoes constant acceleration, what will be the shape of the position-time graph that shows the object's motion? A. linear horizontal B. quadratic function shape C. linear rising to the right D. cubic function shape This would be a linear function right? So either A or C? @perl :)

OpenStudy (eyust707):

What level physics is this?

OpenStudy (anonymous):

just general physics i guess :P

OpenStudy (eyust707):

Calc or non-calc based

OpenStudy (anonymous):

*first year physics if that makes more sense haha :)

OpenStudy (anonymous):

non calc based :)

OpenStudy (eyust707):

ok

OpenStudy (perl):

if a = k v = k*t + c1 x = k*t^2/2 + c1*t + c2

OpenStudy (perl):

so its B

OpenStudy (eyust707):

Yes @perl but that is using calculus

OpenStudy (anonymous):

ohh so it wasn't a linear shape! oh so with or without calculus, would it still be B?

OpenStudy (eyust707):

its B, he just explained it in a way that would only make sense if youve taken calc.

OpenStudy (anonymous):

ohh okay... well i've taken calc already, but my physics course isn't a physics with calculus course, just general physics :)

OpenStudy (eyust707):

If you are curious I will explain it in a way that makes sense to you.

OpenStudy (anonymous):

okay, that'd be nice too! :D

OpenStudy (eyust707):

Ok if acceleration is constant than its graph looks like this|dw:1414475224275:dw|

OpenStudy (eyust707):

flat just one constant value

OpenStudy (eyust707):

And we know from the previous problem i helped you with that acceleration is the rate that velocity is changing, or the slope of the v vs. t graph

OpenStudy (anonymous):

okay :) and yes:D

OpenStudy (eyust707):

Something that has "constant slope" is a line |dw:1414475306254:dw|

OpenStudy (anonymous):

okay:)

OpenStudy (eyust707):

But what about position.. Velocity is the rate at which position changes (your "speed" in a sense) So velocity is the slope of the x vs. t graph

OpenStudy (eyust707):

but as you can see velocity starts at 0 and increases more and more. That means we need a graph whose slope starts out flat and increases more and more

OpenStudy (anonymous):

yes:)

OpenStudy (eyust707):

|dw:1414475575161:dw|

OpenStudy (eyust707):

Awe there we go a graph whose slope starts out flat and increases more and more.

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