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\[\frac{ 1 }{ 1-x ^{2} }\]
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well i though the ones cancel each other out to = -x^2 and that becomes 2x
but im pretty sure thats not right
That sounds right to me so far, I'm not sure though because I haven't seen your answer.
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what do you mean answer?
What are you getting for the derivative?
2x
kainui is such a smart girl who fflutters calculus
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is that the answer
What is the answer? Where?
\[\frac{ 1 }{ 1-x^2 }\] can also be expressed as: \[(1-x^2)^{-1}\] using chain rule to differentiate you'll have: \[-1(1-x^2)^{-2} (-2x)dx\] \[2x (1-x^2)^{-2}dx\] \[\frac{ 2x }{ (1-x^2)^{2} } dx\]
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