How do i differentiate x-2/x^2
do you mean (x-2)/x^2 or x - 2/x^2
(x-2)/x^2
\[\frac{ d \frac{ u }{ v}}{ dx }=\frac{ v*\frac{ du }{ dx } - u*\frac{ dv }{ dx }}{ v^2 }\]
u=x-2 v=x^2
can u do it now ??
No sorry. I get to the stage where i have simplified it to be \[\frac{ 1 }{ x } - \frac{ 2 }{ x^2 }\] But i don't know how to get the rational expression into a negative power.
u got the wrong ans
u=x-2 and v= x^2 find du/dx and dv/dx and put in the formula i gave earlier
I have converted the \[\frac{ 1 }{ x }\] to \[x^-1\] but i don't know how to convert \[\frac{ 2 }{ x^2 }\] . Can you please show me how you can convert it... I know how to do the rest....
\[\large \dfrac{1}{a^n} = a^{-n}\]
\[\large \dfrac{2}{x^2} = 2 \times \dfrac{1}{x^2} = 2 \times x^{-2}\]
is there a reasons why you times by 2 if the original question is divided by 2
multiply \(\large a\) and \(\large \dfrac{1}{b}\) what do you get ?
a/ab
\[\frac{ a }{ab }\]
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