Question

help pleasee

Answer 1

What are the possible numbers of positive real, negative real, and complex zeros of
f(x) = -7x4 - 12x3 + 9x2 - 17x + 3?

Positive Real: 3 or 1
Negative Real: 1
Complex: 2 or 0

Positive Real: 3 or 1
Negative Real: 2 or 0
Complex: 1

Positive Real: 1
Negative Real: 3 or 1
Complex: 2 or 0

Positive Real: 4, 2 or 0
Negative Real: 1
Complex: 0 or 1 or 3

Answer 2

@iGreen @anonymous_user @perl @ryanwhite499 @waterineyes

Answer 3

your life is in my hands

Answer 4

Our lives in your hands?? Really?? Oh I am just scared.. :)

Answer 5

\[f(x) = -7x^4 - 12x^3 + 9x^2 - 17x + 3\] the coefficient have 3 changes in sign
from \(-12\) to \(+9\)
from \(+9\) to \(-17\) and from \(-17\) to \(+3\)
so there could be 3 positive real zeros
count down by twos, so either 3 or 1 positive real zero

Answer 6

before worrying about the negative ones, lets look at your choices

Answer 7

ok

Answer 8

so it would have to be either 1 or b because 3 positive real zeros

Answer 9

3 sign changes for f(x), so there will be 3 zeroes or 1 zero

Answer 10

only the first two fit that bill
3 or 1 positive

Answer 11

i mean a or b

Answer 12

yes, what you said
and b makes no sense, since complex zeros come in conjugate pairs (no one can eat just 1)
that eliminates b

Answer 13

your live is saved, my work here is done

Answer 14

assassination complete thx