Radical equation... please help??

Question

anonymous · Answer

How to solve this...

anonymous · Answer

square both sides to eliminate the radical.  when you solve for 'y', double check your solutions by plugging them into the original equation (to see if any solutions are extraneous)

anonymous · Answer

I've just missed my class this morning :( I don't understand extraneous..
Can you show me a visual? Thank you for your help though

anonymous · Answer

well, sometimes when you solve for variables under a radical, you have to square (to eliminate the radical) -- this could lead to solutions that don't make sense if the radical was still there.  in this particular case, though, there are no extraneous solutions.

i'll give an example of extraneous solution later

anonymous · Answer

Should I solve for 5y + 4 = 8y - 23...is that correct?

anonymous · Answer

correct

anonymous · Answer

y = 9

anonymous · Answer

ahh I can't believe I didn't know this.. (No sleep) LOL thank you for the help again :)

anonymous · Answer

http://hotmath.com/hotmath_help/topics/extraneous-solutions.html has some examples of extraneous solutions (for your reference later) have a nice day!