Question

What is the change in enthalpy of the following reaction?

Answer 1

@nechirwan please help me

Answer 2

Change in Enthalpy (delta H) = Sum of delta H values of products - Sum of delta H values of reactants

Delta H = [(2)(-411) + (-277)] - [(2)(-360) + (-359)]
Delta H = [(-822) + (-277)] - [(-720) + (-359)]
Delta H = [(-1099) - (-1079)]
Delta H = - 20 kJ


Hope this helps...good luck!