Question

On question 22.

Answer 1

@kirbykirby @ganeshie8

Answer 2

@antonio_xx2 thank you! I don't really know who to tag.

Answer 3

um both

Answer 4

No, I mean, just in general, if you hadn't posted that then nobody would be tagged because I don't know who I should.

Answer 5

huh

Answer 6

Nevermind...

Answer 7

I'll do the first one (problem 16) to get you started

---------------------------

Statement 1 is "<2 and <5 are supplementary"
Reason 1 is "Given"

Most of the time, you start with what you are given. It is a very common starting point and if you get stuck, you can at least start with the given.

---------------------------

Statement 2 is already filled in
Reason 2 is "Vertical angle theorem"

The Vertical angle theorem is the idea that vertical angles are congruent. Angles 2 and 3 are congruent because they are vertical angles.

---------------------------

Statement 3 is already filled in.
Reason 3 is "Substitution" (not 100% sure though)

There are a few missing steps here, but the idea is that if "<2 and <5 are supplementary" AND <2 = <3, then "<3 and <5 are supplementary". Notice how I replaced angle 2 with angle 3.

----------------------------

Statement 4 is "L || m"
Reason 4 "Converse of the same side interior angles theorem"


The last statement is ALWAYS what you want to prove. The reason is basically paraphrased to "if the same side interior angles are supplementary, then the lines are parallel"

Answer 8

is that it @jim_thompson5910

Answer 9

what do you mean?

Answer 10

is there any more infoemation or somrthing

Answer 11

that's all i can think of for 16

Answer 12

Yeah, that looks right! Thanks so much.

Answer 13

you'll do the others the same way

Answer 14

you're welcome

Answer 15

So for q 17, the paragraph proof, that would be along the same lines, with the statements and reasons, just written less formally and in paragraph form, correct? @jim_thompson5910

Answer 16

@antonio_xx2 are you doing this test too or something?

Answer 17

lol no i just trying to help u out:)

Answer 18

oh, thanks haha!

Answer 19

ya sure

Answer 20

Okay I've got question 17. Question 18 I'm not sure of.

Answer 21

i gtg @jim_thompson5910 help

Answer 22

for 18, you would use the slope formula

\[\Large m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\]

Answer 23

so -4-5/9--2?

Answer 24

yes and evaluate that

Answer 25

-9/11?

Answer 26

good

Answer 27

So is that the slope?

Answer 28

@jim_thompson5910

Answer 29

yes it is

Answer 30

So for question 19, would I use the slope-intercept formula there too? @jim_thompson5910

Answer 31

you need the slope, then you use either point to find the y-intercept

Answer 32

Okay, so to get the slope I'd use the slope formula. That equals.. 4 to be the slope? So, I'm not sure how to find the y-intercept though, or really what that means.

Answer 33

m = 4 is the slope

Answer 34

say we pick the first point (-1,-4)

so (x,y) = (-1,-4)

x = -1
y = -4

Answer 35

y = mx+b

y = 4x+b

-4 = 4*(-1)+b

solve for b

Answer 36

b=8

Answer 37

so that's the formula

Answer 38

Okay, 20 I know how to do.

Answer 39

Okay, question 21 I'm not sure of. I have to find the equation for the vertical line that goes through (10, 3). I don't know how to go about finding that equation. As you can tell, equations are not my strong suit. @jim_thompson5910

Answer 40

hint: draw a vertical line through (10,3). What other points lie on this line? Plot a few, like 3 or 4. What do you notice about every point on this line? What do they have in common?

Answer 41

Well they all have 10 = x but the y varies because it is on the x = 10 line

Answer 42

so the final answer is x = 10

Answer 43

x = 10 means x is fixed to be 10 always

y is whatever you want

Answer 44

ohhhhh I get it!

Answer 45

it's a bit strange since most of the equations are things like y = 2x+3 or y = -5x-7

things in y = ... form

Answer 46

Yeah, but if you had a horizontal line couldn't it be, say, y=3?

Answer 47

same point (10,-3) ?

Answer 48

No, just in general. y doesn't always have to equal a long, complicated equation if a line is horizontal

Answer 49

yeah if it is horizontal, it is y = SOMENUMBER

ex: y = 3 like you said or y = 10


y = 3 goes through points with y coordinates of 3
y = 10 goes through points with y coordinates of 10
etc etc you get the picture

Answer 50

yeah, okay, that's what I thought.
How about question 22? For that, all I have to do is graph it and see, right?

Answer 51

you have to describe how to construct a square with a given side length (using compass and straightedge only)

Answer 52

Oh sorry I was looking at 23 :p

Answer 53

23 you find the slope of each

if the two slopes multiply to -1, then they are perpendicular

Answer 54

Yeah, question 22 I don't have any idea how to do.

Answer 55

check out

http://www.mathopenref.com/printsquare.html

Answer 56

okay, so 23 - the slope of the first given is 2/3, and the second is 11/8

Answer 57

2/3*11/8=11/12. So they're not perpendicular?

Answer 58

2/3 is close
11/8 is close

Answer 59

both slopes are incorrect

Answer 60

Oh

Answer 61

wait, -2/3 and -11/8?

Answer 62

-2/3 good for the first one
-11/8, no that is still wrong

Answer 63

in the numerator you will have -5-(-6) = -5+6 = 1

Answer 64

1/8

Answer 65

good, so -2/3 and 1/8

Answer 66

so now multiply them you said?

Answer 67

yes

Answer 68

-2/3*1/8=-1/12

Answer 69

the result is not -1, so the two lines aren't perpendicular

Answer 70

Awesome! let me type in my short answer hold on

Answer 71

this animation is very handy for 22

http://www.mathopenref.com/constsquare.html

Answer 72

basically the first link, but in movie form

Answer 73

Done. Now for question 22. I will look at the two links you gave me.

Answer 74

you can have it autoplay all steps through, but I recommend you go through step by step manually so you set your own pace

Answer 75

Oh, I just watched that, that's really helpful

Answer 76

Phew, I'm done. Thank you so much for all your help. I would fan you but my thing is bugging and won't go past 'checking fan status'.

Answer 77

that's ok

Answer 78

this site is a bit weird sometimes