Question

Please help me find the product of this rational expression

Answer 1

I will help you if you are willing to help yourself first.. :)

Answer 2

\[\frac{a}{b} \cdot \frac{c}{d} = \frac{a \times c}{ b\times d}\]

Answer 3

Numerator multiplies with numerator and denominator with denominator.. Okay??

Answer 4

Yep I know that.

Answer 5

Oh, I did not know that, that is why I was just confirming that from you.. :P

Answer 6

I've gotten \[\frac{ 54 }{ 8a }\] but I guess that's incorrect (I got it wrong on my assignment) I appreciate you helping me work it out.

Answer 7

Why not, if you will not appreciate me then I will kill you.. :P

Answer 8

You are right in multiplying but you have not reduced it to simpler form or you can say you have not simplified it.. :)

Answer 9

\[\frac{54}{8a}\]

Answer 10

would it be \[\frac{ 27 }{ 4a }\] then?

Answer 11

Oh my goodness, you are faster than me.. :) Well done.. :)

Answer 12

Ha I don't know why I didn't simplify it. Duh :P thanks so much for your help!

Answer 13

Could you help me with one more? @waterineyes

Answer 14

sure, go ahead.. :)

Answer 15

you try first.. :)

Answer 16

Okay I got: \[\frac{ -2x^2 }{ y }\]

Answer 17

@waterineyes

Answer 18

One mistake..

Answer 19

\[x^2 \cdot x = ?? \]

Answer 20

x^3? :)

Answer 21

yep, then why are you not multiplying \(x\) terms?? angry with \(x\) terms?

Answer 22

Ha no I just forgot I suppose, so it would be\[\frac{ -2x^3 }{ y }\] ?

Answer 23

Oh sorry I did not notice one more mistake. :(

Answer 24

What would it be?

Answer 25

It seems like you want to take one \(-\) sign to home with you?

Answer 26

oops! \[\frac{ -2x^3 }{ -y }\] ?

Answer 27

See, when numerator and denominator both have negative signs, they get cancelled.. :)

Answer 28

\[\frac{-2x^3}{-y} = \frac{\cancel{-} 2x^3}{\cancel{-} y} = \frac{2x^3}{y}\]

Answer 29

Getting?

Answer 30

I see now

Answer 31

Suppose there is one sign in numerator and two in denominator, then??

Answer 32

\[\frac{-}{- \cdot -}\]

Answer 33

you can simply say that in denominator \(- \cdot - = +\), so:
\[\frac{-}{- \cdot -} = \frac{-}{+} = -\]

Answer 34

Or you can cancel one -ve sign with -ve sign, then also you will remain with one,..

And if you have one sign in denominator, you can shift that negative sign to numerator, it looks nice:
\[\frac{x}{-y} = \frac{-x}{y}\]

Getting?

Answer 35

yes I think so

Answer 36

Great.. :)