Question

how do you turn this into standard form: -(x-2)^2 +1

Answer 1

multiply out and combine like terms
start with
\[-(x-2)(x-2)+1\] and go from there

Answer 2

or you might remember that \(9a+b)^2=a^2+2ab+b^2\) so
\[(x-2)^2=x^2-4x+4\] giving
\[-(x^2-4x+4)+1\] then distribute the minus sign, then add 1

Answer 3

Thanks for answering my question! So, would the answer be -x^2 + 4x - 3 ?

Answer 4

yes

Answer 5

Thanks!!! And to take a function in vertex form and turn it into standard form, would you use the same method?

Answer 6

it was in vertex form

Answer 7

vertex form is
\[y=a(x-h)^2+k\]

Answer 8

how would I turn the standard form back into vertex form ?

Answer 9

a) complete the square or
b) find the vertex

Answer 10

Ohh okay thanks!!

Answer 11

yw
i find it easier to find the vertex, but either way works