Question

simplifying expression,do anyone know about it?

Answer 1

heard of it

Answer 2

Not only have i heard of it, i am somewhat decent at it....

Answer 3

with radicals? and an exponent \[\sqrt[6]{8a^6}b^9 c^12\]

Answer 4

it always bothers me.

Answer 5

\[\huge \sqrt[6]{8a^6b^9 c^{12}}\]

Answer 6

yes that's it.

Answer 7

that is my guess
i could be wrong

Answer 8

thats the equation.

Answer 9

6 goes in to 6 once, with no remainder
out comes an \(a\)

Answer 10

6 goes on to 9 once with a remainder of 3
out comes a \(b\) in stats a \(b^3\)

Answer 11

6 goes in to 12 two times
out comes a \(c^2\)

Answer 12

ohh, so you solve it by exponent.

Answer 13

we are not done though
at the moment we have
\[\huge abc^2\sqrt[6]{8b^3}\]

Answer 14

or
\[abc^2\sqrt[6]{2^3b^3}\]

Answer 15

since \(\frac{3}{6}=\frac{1}{2}\) you can write this as
\[\huge abc^2\sqrt{2b}\]

Answer 16

oh, Awesome thank's. :)

Answer 17

yw

Answer 18

Can I ask you another math question?

Answer 19

it's alittle similar.

Answer 20

\[\sqrt[4]{256}a^12\]