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Can someone please help me figure this out? It is a simple question. Medal to best answer. Rubidium has two naturally occurring isotopes, rubidium 85 (atomic mass = 84.9118 amu; abundance = 72.15 percent) and rubidium-87 (atomic mass = 86.9092 amu; abundance = 27.85 percent) Calculate the average atomic mass of rubidium. 86.0000 amu 85.9105 amu 8576.80 amu 85.4680 amu
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It's a weighted average. Multiply the mass of each isotope by it's percent abundance, then add these values together.
(84.9118 x 72.15) + ( 86.9092 x 27.85 ) / 100 =85.47 amu
Okay. So, I would multiply 85 by 0.7215? And then -87 by 0.2785? etc.
oh okay. but wouldn't the 72.15 be 0.7215?
never mind. So the answer would be the last one?
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