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Mathematics 20 Online
OpenStudy (anonymous):

a catapult launches a boulder with an upward velocity of 148 ft/s. the height of the boulder, h, in feet after t seconds is given by the function h=-16t^2+148t+30. what is the bolders maximum height? how long does it take the boulder to reach its mamimum height? round to nearest hundredth if necessary. -reaches a maximum height of 30 feet after 9.25 seconds -reaches a maximum height of 640.5 feet after 4.63 seconds. -reaches a maximum height of 1,056.75 feet after 4.63 seconds. -reaches a maximum height of 372.25 feet after 4.63 seconds.

OpenStudy (anonymous):

@godofwar

OpenStudy (perl):

use the formula x = -b / (2a)

OpenStudy (anonymous):

i tryed

OpenStudy (anonymous):

im doing something wrong

OpenStudy (perl):

x = - (-148) / ( 2 * -16) =

OpenStudy (anonymous):

-1,184

OpenStudy (perl):

thats wrong, did you use order of operations?

OpenStudy (anonymous):

oops 4.625

OpenStudy (anonymous):

-(-148)= 148 then (2*-16)= -32 coming to 4.625

OpenStudy (anonymous):

148/-32

OpenStudy (anonymous):

^ forgot setp=4.625

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