a catapult launches a boulder with an upward velocity of 148 ft/s. the height of the boulder, h, in feet after t seconds is given by the function h=-16t^2+148t+30. what is the bolders maximum height? how long does it take the boulder to reach its mamimum height? round to nearest hundredth if necessary.
-reaches a maximum height of 30 feet after 9.25 seconds
-reaches a maximum height of 640.5 feet after 4.63 seconds.
-reaches a maximum height of 1,056.75 feet after 4.63 seconds.
-reaches a maximum height of 372.25 feet after 4.63 seconds.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@godofwar
OpenStudy (perl):
use the formula x = -b / (2a)
OpenStudy (anonymous):
i tryed
OpenStudy (anonymous):
im doing something wrong
OpenStudy (perl):
x = - (-148) / ( 2 * -16) =
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
-1,184
OpenStudy (perl):
thats wrong, did you use order of operations?
OpenStudy (anonymous):
oops 4.625
OpenStudy (anonymous):
-(-148)= 148 then (2*-16)= -32 coming to 4.625
OpenStudy (anonymous):
148/-32
Still Need Help?
Join the QuestionCove community and study together with friends!