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Mathematics 14 Online
OpenStudy (anonymous):

math help? connections?

OpenStudy (anonymous):

first set of questions http://prntscr.com/51pr7w second set http://prntscr.com/51pr0y

OpenStudy (mathstudent55):

1. is correct

OpenStudy (anonymous):

i knew that one was gonna be right, but the other ones confuse me so much

OpenStudy (mathstudent55):

2. the angles have to add to 90 degrees to make right angles at the corners

OpenStudy (mathstudent55):

3. if you read the problem, you notice that only Adams, Bertha and Charles are mentioned. We don't anything about the other two streets.

OpenStudy (anonymous):

so for 2 would it be a=30 and b=60 since those add up to 90?

OpenStudy (mathstudent55):

Correct

OpenStudy (mathstudent55):

Now look at 3.

OpenStudy (mathstudent55):

Read my explanation about 3. above.

OpenStudy (anonymous):

bertha is parallel to charles is correct

OpenStudy (cicilybailey14):

@mathstudent55 I was confused on this too...you actually helped me out lol

OpenStudy (mathstudent55):

|dw:1414787200212:dw|

OpenStudy (mathstudent55):

Adams is a perpendicular to two streets. What can you tell about Bertha and Charles?

OpenStudy (mathstudent55):

@Cicilybailey14 Thanks for letting me know. I'm glad I was able to help you.

OpenStudy (mathstudent55):

Oh, I see, you got it already. Yes, Bertha is parallel to Charles. you are correct. Now let's move on to 5.

OpenStudy (mathstudent55):

The best way to deal with a problem like this is to draw it.

OpenStudy (anonymous):

wait, is 3 and 4 bertha is perpendicular to charles?

OpenStudy (mathstudent55):

I started it for you. Here is line a. Now you need b perpendicular to a. Use my drawing, and add b perpendicular to a. |dw:1414787444894:dw|

OpenStudy (mathstudent55):

Wait. I skipped 4. Let me go back to it.

OpenStudy (mathstudent55):

For 3. Bertha is parallel to Charles. Now let's do 4.

OpenStudy (anonymous):

ok

OpenStudy (mathstudent55):

|dw:1414787638654:dw|

OpenStudy (anonymous):

wouldnt adams ct be perpendicular to edward rd as well

OpenStudy (mathstudent55):

Yes. If a line is perpendicular to one of two parallel lines, it is perpendicular to both parallel lines.

OpenStudy (anonymous):

now to 5

OpenStudy (mathstudent55):

Notice that choices b, c, d mention Dana and Berth which we are not told anything about in this problem. The answer is A.

OpenStudy (mathstudent55):

Ok, problem 5. Let me look above for what I already did.

OpenStudy (anonymous):

|dw:1414787847724:dw| would this be how its done

OpenStudy (mathstudent55):

The best way to deal with a problem like 5 is to draw it.

OpenStudy (anonymous):

you said add the perpendicular line?

OpenStudy (mathstudent55):

Good, but make b longer going below a also.

OpenStudy (anonymous):

|dw:1414787945893:dw|

OpenStudy (mathstudent55):

Excellent. Now we add the little perpendicular symbol to remind us the lines are given as perpendicular. |dw:1414787951762:dw|

OpenStudy (mathstudent55):

Now we add a line c, which is perpendicular to b. Draw line c below line a, just because it fits better in our drawing.

OpenStudy (anonymous):

like this or would you like it at the tip of b |dw:1414788089505:dw|

OpenStudy (mathstudent55):

|dw:1414788112833:dw|

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