Question

guys can you tell me of this function actually has 3 roots>

Answer 1

according to the graph i have i not sure if 2 is actualy a root

Answer 2

Is the function even defined at x=2 ?

Answer 3

hmm not sure

Answer 4

x=2 pulls the denominator to 0
so the funciton as it stands is not defined at x = 2

Answer 5

well the factor cancels out (x-2)

Answer 6

thats still worse because you get a hole at x=2

Answer 7

oh right

Answer 8

so it not defined

Answer 9

so only -2 and 0 are the roots right

Answer 10

looks good

Answer 11

do you know what type of discontinuity the graph has at x = 2 , could it be jump or hole ?

Answer 12

we call it a hole if the common factor cancels out

Answer 13

ohh i see

Answer 14

Thank you my friend :D.

Answer 15

np :)
see http://www.mathwords.com/r/removable_discontinuity.htm

Answer 16

:D

Answer 17

1 and 2 are roots.