Create your own polynomial with a degree greater than 2. Find the zeros of the function. could someone walk me through on how to do this? I don't get what "find the zeros" means..
mathematicians use different words for the same thing zeros = roots = x intercepts
I tend to use the word roots more than 'zeros' so we can look at a factored form a polynomial, in terms of its 'roots' y = a ( x - r1) (x-r2) (x-r3)... (x-rn) , where r1,r2,..rn are roots
so you want a polynomial of degree greater than 2, so you will need at least 3 factors y = a ( x - r1 ) ( x - r2) ( x - r3) , now pick any values for r1, r2, r3 and you can let 'a' equal 1 , since thats easiest
sorry, i still don't really get what you're saying :(
i had another question that said "Using complete sentences, explain how to find the zeros of the function f(x) = 2^3 – 9x + 3." i wrote that you would try to find the x values in this to check if they came out to 0, is that right?
function f(x) = 2^3 - 9x + 3.
is there an x missing
f(x) = 2x^3 - 9x + 3.
ok, thats a cubic polynomial
it is difficult to factor these generally, but sometimes it has nice x intercepts (roots) which I find by graphing it
alternatively you can use rational roots theorem, but this theorem won't guarantee you rational roots exist
the theorem says *if* rational roots exist, then the roots will have such and such form
if f(p/q) = 0 , then p divides the constant coefficient and q divides the coefficient of the degree term
and check out wolfram, it does a lot of the tedious stuff. here is what i will submit into wolfram "solve 2^3 - 9x + 3= 0 " (this gives us the roots)
Wolfram gives me one real rational root x = 11/9 http://www.wolframalpha.com/input/?i=solve+2^3+-+9x+%2B+3%3D+0
so now you can do synthetic/long division and factor out (x -11/9) ,
alternatively, you could use something called the cubic formula, but its probably outside the scope of your class or homework
and it would be overkill in this example to use cubic formula
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