Question

How do I find the absolute value of 6-16i ?

Imaginary numbers are awful

Answer 1

HINT:
absolute value of a complex quantity (A+iB) is
\[A=\sqrt{A^2+B^2}\]

Answer 2

\[Z=\sqrt{A^2+B^2}\]

Answer 3

multiply by the congugate then take the square root to find the modulus...
|6-16i| = sqrt{(6-16i)(6+16i)}

Answer 4

if \(z=a+bi\) then \(|z|=\sqrt{zz^*}=\sqrt{(a+bi)(a-bi)}=\sqrt{a^2+b^2}\)

Answer 5

\[\sqrt{36+256}= \sqrt{292}\]

Answer 6

I dont understand what to do after that

Answer 7

yes thats correct thats the absolute value of the complex quantity

Answer 8

Thats it?

Answer 9

yup ,u could simplify it a little bit
\[\sqrt{292}=17.08\]

Answer 10

Awesome thanks :)

Answer 11

yw!!!