Question

Not too bright in math
Help please?
fan, medal, testimony

Answer 1

You can make use of the fundamental trigonometric relation:
cos^2(x) + sin^2(x) = 1

Answer 2

z/y

Answer 3

tan(x) = sin(x)/cos(x) => sin(x) = tan(x)*cos(x) = (z/10)*(10/y), so
sin(x) = z/y

Answer 4

I get what youre saying, and it made me understand. but not for tis question. would I use the cos equation? @M4thM1nd

Answer 5

This is a 90deg triangle, so cos(50) = y/z => z = y/cos(50)

Answer 6

if you understand the ralations between sin, cos and tan and the sides of the 90deg triangle this kind of question can be solved very easily

Answer 7

For instance, in this same question:
sin(50) = x/z
cos(50) = y/z
tan(50) = x/y

Answer 8

In addition, you can use z^2 = x^2 + y^2 to solve others problems too

Answer 9

In that case, for this question, the answer is C?

Answer 10

Consider the triangle ABC, then sin(60) = 9/AB, so
AB = 9/sin(60)

Answer 11

ugh ): im a lost cause in math, im sorry @M4thM1nd

Answer 12

Here's one way of doing it:


Remember \[\LARGE \tan x = \frac{\sin x}{\cos x}\] So if you multiply both sides by cos x you get:

\[\LARGE \cos x \tan x = \sin x\]

Now since you're given both cos x and tan x you can multiply them together to get sin x.

Answer 13

Oh there are multiple questions here, oh well.

Answer 14

Remember that the hyponenuse is the opposite side of the 90 deg angle

Answer 15

sin of an angle "o" is the defined as (opposite side of angle "o")/(hypotenuse).
cos of an angle "o" is the defined as (adjcente side of angle "o")/(hypotenuse).

Answer 16

tan of an angle "o" is the defined as (opposite side of angle "o")/(adjcente side of angle "o").

Answer 17

So for this question id say that we relate because of the fact that they're hypotenuse?

Answer 18

In the image of this last question, if i want to calculate sin(60), teh opposite side of angle 60 is 9 and the hypotenuse is AB, so sin(60) = 9/AB