Question

Solve the triangle.

A = 52°, b = 10, c = 7

Answer 1

@Hero @zepdrix

Answer 2

Drawing a picture might help

Answer 3

ur right I kept drawing it as a right triangle so that made a huge difference

Answer 4

oh hehe

Answer 5

Looks like we have to apply the Law of Cosines here.
I don't think we have enough information for Law of Sines.

Answer 6

what is the law again?

Answer 7

\[\Large\rm a^2=b^2+c^2-2bc cosA\]I've written it a little different here, because we want to use angle A.

Answer 8

Normally it looks like:\[\Large\rm c^2=a^2+b^2-2ab~\cos C\]

Answer 9

oh yeah I remember! So does that make a=12?

Answer 10

i dunno, im not that fast lol.. hold on XD

Answer 11

LOL sorry

Answer 12

Hmm, no I'm not coming up with 12.
Let's see what's going on.

Answer 13

i did it one time and i got 7.9 but i thought that was wrong could that be it? or am i completely off?

Answer 14

\[\Large\rm a^2=b^2+c^2-2bc~cosA\]\[\Large\rm a^2=10^2+7^2-2(10)(7)~\cos(52^o)\]

Answer 15

\[\Large\rm a^2=149-140\cos(52^o)\]\[\Large\rm a^2=149-86.2\]\[\Large\rm a^2=62.81\]

Answer 16

Ya it looks like the 7 point something is what we were looking for.

Answer 17

Taking the square root,
I'm coming up with something like 7.925

Answer 18

yay ok is C=43.9?

Answer 19

it keeps feeling wrong

Answer 20

Law of Sines gives us:\[\Large\rm \frac{\sin(52^o)}{7.93}=\frac{\sin(C)}{7}\]Solving that gives ussssss,
Yah looks like about 44 :)

Answer 21

cool thank you so much I can find the next one myself! :)

Answer 22

cool c: