Find the function with the given derivative whose graph passes through the point P.
fprime(x)=e^(2x) P(0,3/2)
so you have to integrate or find the anti-derivative of f ' (x)=e^(2x). Then use the point to determine the value of c.
how would you go about finding the anti derivative of an exponential?
\[\frac{ d }{ dx }e^x=e^x\]
\[\frac{ d }{ dx}e^{f \left( x \right)}=f^{\prime}\left( x \right)\cdot e^{f \left( x \right)}\]
f(0)=2e^(2x)?
\[\int\limits f^{\prime}\left( x \right)\cdot e^{f \left( x \right)}\,\,dx=e^{f \left( x \right)}+C\]
no, find f(x) first. to be sure you have the correct function, take its derivative and verify that it equals the derivative function you were given.
once you have the correct function, then evaulate it when x = 0 and set the result equal to 3/2. remember, you will have a constant of integration. the derivative of a constant is 0 and that is why it doesn't show in the derivative.
you there?
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