Question

What is the equation of the quadratic graph with a focus of (−4, −five fourths) and a directrix of y = twenty seven fourths?

f(x) =negative one sixteenthsx2 − one half x + seven-fourths

f(x) =negative one sixteenthsx2 − one half x + thirteen fourths

f(x) =one sixteenthsx2 + one half x + seven-fourths

f(x) =one sixteenthsx2 + one half x + thirteen fourths
CAN U PLEASE HELP ME? @hartnn

Answer 1

hello? @hartnn

Answer 2

solved any similar problem before ?

Answer 3

nope

Answer 4

http://hotmath.com/hotmath_help/topics/finding-the-equation-of-a-parabola-given-focus-and-directrix.html

have a look :)

Answer 5

see the example
we can use similar approach for this problem

Answer 6

Distance between (x,y) and (-4,-4/5) is ??

Answer 7

this is so hard

Answer 8

if you know the distance formula, then it isn't

Answer 9

Distance between points (x1,y1) and (x2,y2) is
\(\huge d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\)

Answer 10

so once again

Distance between (x,y) and (-4,-4/5) is ??

Answer 11

where is x^2?

Answer 12

which x^2 ?

use the points and the formula i gave to find the distance

x1 = x
y1 =y
x2 =-4
y2= -4/5

Answer 13

ooohh ok

Answer 14

\[\sqrt{-4}-(-4)^{2} +(\frac{ -5 }{ 4}-(-\frac{ 4 }{ 5})^{2}\]

Answer 15

@hartnn

Answer 16

where is x and y ? :O