Question

Linear approximation
f(x)=12-x^2; a=2 f(2.1)
Got the first parts equation is y=-4x+16
Second part f(2.1) = 7.6
How do I find percent error?

Answer 1

sounds like you need to find the difference between the actual and approximation
\[|\frac{actual-approximation}{actual} |\cdot 100 \%\]

Answer 2

So what's my aproximation that's the part I don't get ?

Answer 3

\[f(x)=12-x^2 \approx -4x+16 \text{ for values of x near a=2}\]

Answer 4

-4x+16 gives approximations
12-x^2 gives actuals

Answer 5

Oooo ok :) yay got it

Answer 6

after all the line you found is called a linear approximation

Answer 7

to the function given