Calculate the molarity of 1.0 liter of solution made with the following solutes...
a.) 2.3g of NaCl
b.) 1.2 grams of calcium carbonate
c.) 0.09 grams of sodium sulfate

Question

Calculate the molarity of 1.0 liter of solution made with the following solutes...
a.) 2.3g of NaCl
b.) 1.2 grams of calcium carbonate
c.) 0.09 grams of sodium sulfate

anonymous · Answer

@cuanchi

anonymous · Answer

Get moles of all compounds

1.) 2.3g NaCl * 1 moles Nacl
                        58.5Grams Nacl
    mole .039 Nacl

.039moles Nacl/ 1L= .039Molarity

2.) 1.2g CaCO3 * 1mole CaCO3
                           100.869 Grams CaCO3
mole  .012 CaCO3

.012/1L= .012 Molarity

3.) 0.09 NaSO4 * 1 mole NaSO4
                           100.87 Grams NaSo4
mole 6.34*10^-4 NaSO4

6.34*10^-4/1L= 6.34*10^-4 Molarity