Create a quadratic function, f(x), in vertex form. The a should be between 4 and –4, the h will be your birth month, and the k will be your birth day. Write your equation below.
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OpenStudy (anonymous):
My birthday is 11/23/96
jimthompson5910 (jim_thompson5910):
so h = 11 and k = 23
jimthompson5910 (jim_thompson5910):
pick an 'a' value between 4 and -4
jimthompson5910 (jim_thompson5910):
then plug all 3 values into
\[\Large y = a(x-h)^2 + k\]
jimthompson5910 (jim_thompson5910):
that equation is the general vertex form equation
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OpenStudy (anonymous):
how about 2
jimthompson5910 (jim_thompson5910):
sure a = 2 works
OpenStudy (anonymous):
okay now what do I do?
jimthompson5910 (jim_thompson5910):
plug a = 2, h = 11, k = 23 into that equation I wrote above
OpenStudy (anonymous):
2(x-11)^2+23
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jimthompson5910 (jim_thompson5910):
correct
OpenStudy (anonymous):
Can you help me with the rest of the questions for this problem?
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
how many more are there?
OpenStudy (anonymous):
5 more
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jimthompson5910 (jim_thompson5910):
ok we'll see (depends on how long they are)
OpenStudy (anonymous):
Using complete sentences, explain how to convert your birthday function into standard form.
jimthompson5910 (jim_thompson5910):
so we have 2(x-11)^2+23 which is currently in vertex form
jimthompson5910 (jim_thompson5910):
we need to get it into ax^2 + bx + c form
jimthompson5910 (jim_thompson5910):
to do that, you need to FOIL or expand out (x-11)^2 first
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jimthompson5910 (jim_thompson5910):
what does (x-11)^2 expand out to?
OpenStudy (anonymous):
(x-11)(x-11)?
jimthompson5910 (jim_thompson5910):
FOIL that out
OpenStudy (anonymous):
x^2-11x-x^2-11x
jimthompson5910 (jim_thompson5910):
how did you get x^2 twice?
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OpenStudy (anonymous):
oops
jimthompson5910 (jim_thompson5910):
to help you expand out (x-11)(x-11), you can use this table
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