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Mathematics 15 Online
OpenStudy (anonymous):

Please help me do this graphing problem anyone??

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

f(x) < 0 is the same as y < 0 because y = f(x)

jimthompson5910 (jim_thompson5910):

so you are looking for intervals where the blue curve is below the x axis below the x axis corresponds to when y < 0

jimthompson5910 (jim_thompson5910):

does that make sense? or no?

OpenStudy (anonymous):

so im gona get something like (2,infinity)(-infinity,1)

jimthompson5910 (jim_thompson5910):

(2,infinity) corresponds to the curve that is above the x axis

jimthompson5910 (jim_thompson5910):

so (2,infinity) is part of the solution for f(x) > 0

jimthompson5910 (jim_thompson5910):

but we want f(x) < 0

OpenStudy (anonymous):

(-infinity,0)

jimthompson5910 (jim_thompson5910):

that's one piece of the answer to part (a)

jimthompson5910 (jim_thompson5910):

there is another piece that is below the x axis

OpenStudy (anonymous):

(-infinity,0),(1,2)

jimthompson5910 (jim_thompson5910):

you combine the two pieces using a U

jimthompson5910 (jim_thompson5910):

U for union

jimthompson5910 (jim_thompson5910):

(-infinity,0) U (1,2)

OpenStudy (anonymous):

B (0,1) U (2,infinity)

jimthompson5910 (jim_thompson5910):

close, but now we have a \(\Large \ge\) symbol and not just a > symbol for part (b)

jimthompson5910 (jim_thompson5910):

so we're including the endpoints 0, 1 and 2

jimthompson5910 (jim_thompson5910):

meaning that the answer for part (b) is really [0,1] U [2, infinity)

jimthompson5910 (jim_thompson5910):

notice how the parenthesis changed to square brackets (to show how we're including those endpoints)

OpenStudy (anonymous):

yeah I see how it works now thank you

jimthompson5910 (jim_thompson5910):

np

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