Mathematics
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OpenStudy (anonymous):
Please help me do this graphing problem anyone??
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OpenStudy (anonymous):
jimthompson5910 (jim_thompson5910):
f(x) < 0 is the same as y < 0
because y = f(x)
jimthompson5910 (jim_thompson5910):
so you are looking for intervals where the blue curve is below the x axis
below the x axis corresponds to when y < 0
jimthompson5910 (jim_thompson5910):
does that make sense? or no?
OpenStudy (anonymous):
so im gona get something like (2,infinity)(-infinity,1)
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jimthompson5910 (jim_thompson5910):
(2,infinity) corresponds to the curve that is above the x axis
jimthompson5910 (jim_thompson5910):
so (2,infinity) is part of the solution for f(x) > 0
jimthompson5910 (jim_thompson5910):
but we want f(x) < 0
OpenStudy (anonymous):
(-infinity,0)
jimthompson5910 (jim_thompson5910):
that's one piece of the answer to part (a)
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jimthompson5910 (jim_thompson5910):
there is another piece that is below the x axis
OpenStudy (anonymous):
(-infinity,0),(1,2)
jimthompson5910 (jim_thompson5910):
you combine the two pieces using a U
jimthompson5910 (jim_thompson5910):
U for union
jimthompson5910 (jim_thompson5910):
(-infinity,0) U (1,2)
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OpenStudy (anonymous):
B (0,1) U (2,infinity)
jimthompson5910 (jim_thompson5910):
close, but now we have a \(\Large \ge\) symbol and not just a > symbol for part (b)
jimthompson5910 (jim_thompson5910):
so we're including the endpoints 0, 1 and 2
jimthompson5910 (jim_thompson5910):
meaning that the answer for part (b) is really [0,1] U [2, infinity)
jimthompson5910 (jim_thompson5910):
notice how the parenthesis changed to square brackets (to show how we're including those endpoints)
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OpenStudy (anonymous):
yeah I see how it works now thank you
jimthompson5910 (jim_thompson5910):
np