Question

how do I graph the total resistance exerted on a series circuit (red, blue and green)?

Answer 1

Plz explain what you mean by Red, Blue and Green.

Answer 2

resistors as in green is 5v blue 10v green 20v

Answer 3

One has to guess what you are trying to say. Use the draw function on the box where you are typing.

Answer 4

You may be confused about electrical terminology. Resistance is generally measured in Ohms, not volts.
Maybe you are being asked about graphing the current through the resistors in a series circuit. If so, a series circuit has one and only one path for current to flow. The current will always be the same at any point in a series circuit at a given time. It will vary according to the voltage applied across the entire circuit. If you have 3 resistors, one being 5 ohms, one is 10 ohms and the last is 20 ohms, the total circuit resistance is (5 + 10 + 20 = 35) 35 ohms.
If you were asked to graph the current versus voltage of a purely resistive series circuit (like the 3 resistors above), you could put the voltage (in Volts) on the X axis and current (in Amps) on the Y axis. The formula for current if voltage and resistance is known is I = E / R, where I is current in Amps, E is voltage in Volts, and R is resistance in Ohms. NOTE: the previous equation is a re-ordered form of the equation E = I R, known as Ohm's Law.
On the graph you can plot what the resultant current would be in the Series Circuit for differing voltages applied. An easy example would be to apply 35 volts to the total circuit resistance of 35 ohms. the current would then be I = 35 volts / 35 ohms = 1 amp. If you double the voltage to 70 volts, the current would be 2 amps.
Because the current is the same anywhere in a Series Circuit, you can also calculate what the voltage would be across any one resistor. As E = I R, the voltage (dropped) across the 10 ohm resistor would be 1 amp * 10 ohms = 10 volts. The voltage drop across each resistor, when added up, will add up to 35 volts for 1 amp of current.
Also note, although the current is the same at any point in a series circuit at any particular time, the voltage drop can vary depending upon the components that make up the Series Circuit. If Capacitors and/or Inductors were also included in the circuit, the voltage and current would vary by time, because at the point immediately following a voltage application, removal, or change, the equivalent resistance of a Capacitor or Inductor will vary. Example, a capacitor looks like a low resistance to voltage change but changes to look like a very high resistance if the voltage applied to the total circuit remains the same. Like wise, an inductor looks like a high resistance to any change in voltage but drops over time to look like a low resistance, again if the voltage applied to the total circuit remains constant.
I hope this might answer your question.