Question

the cartesian coordinates of a point are given. find the polar coordinates (r, theta) of the point where r<0 and 0 <=theta<2pi.

Answer 1

opps this goes with it too, (-1,-sqrt3)

Answer 2

Do you mean \(r>0\) ? Because \(r\) can't be negative.

Answer 3

The reason being that
\[r=\sqrt{x^2+y^2}\]
and the square root is always non-negative when \(x\) and \(y\) are real.

Answer 4

**when \(x^2+y^2>0\), which is the case for all real \(x\) and \(y\), to be more precise**