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.find the domain and range of the quadratic function and state whether the vertex is a maximum or minimum f(x)=-7(x-5)^2-7
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\[(x-5)^2\geq 0\] always, because it is a square that makes \[-7(x-2)^2\leq 0\] and so \[f(x)=9(x-5)^2-7\leq -7\]
then do you graph is
typo on the last line \[f(x)=-7(x-5)^2-7\leq -7\]
vertex is \((5,-7)\) draw a parabola that opens down with that as the vertex
oh
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what about the domain and range
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