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Calculate the pH of a solution prepared by mixing 15.0 mL of 0.10 M NaOH and 30.0 mL of a 0.10 M benzoic acid solution. (Benzoic acid is monprotic; its dissociation constant is 6.5 x 10^-5.)
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Its at the 1/2 eq. pt or when pH = pKa So this problem is finding the pKa pKa = -log [Ka] = -log [6.5 x 10^-5]
This is a weak acid titrated with a strong base.
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