combine like terms. -4m + 12m please explain
If it is like terms, what are the coefficients?
Not coeficients lol the little numbers
See, \(m\) are attached to both the terms, so it reduces to just addition or subtraction to do this problem, just ask yourself that what is \(-4 + 12 = ??\), and with the final answer, just attach \(m\) with it.. :)
you said right, they are coefficients.. :)
yaay thank you guys so much <3 c:
Np
@steph1525 what is the answer you got? Mind telling us so that we can verify it for you?
I wasn't much help tho lol
yeah for me, they are coefficients of \(m\), what are they for you? :P
question @waterineyes
i got -4m+12 is equal too 8m c:
Good.. :)
What question ?? @50centolly
What is the coefficient of m stand for?
okay so is it the same if you are dealing with exponents?
what does not is lol
The digit or number attached to it..
this is kind of confusing for a 4th grader xD
I see
I am in algebra 2 thank u
;) i am just not good at math
\(14m\), here \(m\) is having \(14\) as its coefficient..
6t squared - 2tsquared
Yep, but both should be squared.. :)
yes but how do i figure these out? what do i do with the exponents
Like you have \(t^2\), so \(t^2\) should be with both the terms, then it becomes simply addition or subtraction, but don't forget to attach \(t^2\) with the final result. :)
What is \(6 - 2\) = ??
ooh so basically i subtract 6 and 2 and then add t squared
not add but attach..
yeah that c: omg u guys are so awesome c: my teacher cant even explain this to me right -_-
If you will add \(t^2\) with \(4\), you will get \(t^2 + 4\), you have to just attach \(t^2\) with \(4\) or you can say multiply.. :)
So \(6-2 = 4\), so attach \(t^2\) with it, it will give you : \(4t^2\).. Getting?
yeah i get it sso my next question is -5w cubed + 18w cubed and i got the answer 13w cubed
is that right?
But remember, when the terms are not like terms or they are unlike, then you can't do anything, you have to just leave the answer as it is : Example : If with first term you have only \(t\), and with second term you have \(t^2\), then you can't do anything with it.
Good, that is correct to an infinite extent. :)
yaay c: this is awesome learning should be this simple is school
For example: If you have : \(4t - 15t^2\), now you cannot do anything with it..
Because they are not like terms, they will be like terms if either of them have \(t\) or \(t^2\) with them.
oh okay i get it so my next one is 15nsquared + 17t i just leave it as it is right?
Now can I give you one question so that you can practice it?
of course c:
yes leave as it is, you can't do anything more there.
Do this one : \[m^2 + m^3 + 2m^3 - 4m^2 + m\]
yaay i got it so 4p + 4psquared i just leave as is
Look for the like terms, then add or subtract them, and then tell the final result.
You can leave that as it is but you can do some more by using Distributive Property.
As you can see, 4 is there in both, p is in both, so you can take common things out : Like : \(4p + 4p^2\) \(4p(1 + p)\)
im so nervous they gave me so much extra homework because i am taking a test on friday to determine whether or not i can skip a grade i passed my language arts and science test math is next so im trying to learn asn much as possible
you must @steph1525
i know i am just so nervous :c and what about decimals like -2.6d - 3.4d
They are just like additions, just check for whether they are like terms or not.
See, they both have \(d\) with them, so they are like terms.
So : \(-2.6 - 3.4\) = ??
So, again with the final result attach \(d\) to it.
okay so shoould i add them because 2 negatives equals a positive no?
In addition, yes you will add them, but sign should remain negative, getting?
Like : \(-2 -3\) , you will add it first : you get : \(5\), as both are negative, so just attach \(-\) sign with 5: so finally : \(-5\).
so will it be -6.0d?
Good.. :)
yaaay c:
Just make perfect your addition or subtraction concepts, like and unlike terms can be done in a jiffy.. :)
okay so what about things like 4(x+9) + 5x?
Here comes the Distribution, which I was talking about above.
See, distribution means distribute outer terms to the inner terms separately.
See : \[a(b+c) = ab + ac\]
a is multiplying with inner \(b\) and again the same a is multiplying with inner c..
so i multiply 4 to x and 9?
Then sign between them will be the same sign which was earlier in the brackets. \[a(b-c) = ab - ac\]
Firstly multiply \(4\) with \(x\) ??
okay and that stays as 4x right
you will get : \(4x\) and then multiply \(4\) with \(9\) ?
okay 36
Yeah, you are going quite well, even better than me.. :)
So, now tell me, you will add 4x with 36, or subtract them?
add
You have \(4(x+9)\), see the sign between \(x\) and \(9\) is \)+\), so yes you will add them.
so the answer is 45x right?
Wait.
You got : \(4x + 36\) ? Right?
They are not like terms, see one is only \(36\) and with one there is \(x\), so they are unlike terms, so you can't do anything with them.
yes and i added and then i added the 5x at the end of the eqation because the question was 4(x+9) + 5x
oooohhh okay
so i leave that and what do i do with the 5x
so you get : \(4x + 36 + 5x\), now tell me what more you can do in this?
Hey, use your brain, there are \(x\) attached with two terms, so you should do what?
i can add the 4 and 5 and get 9x +36
Excellent.. :)
yaay c:
No matter how many problems, you have got, but I tell you, these are the basic things if you have, you can conquer any problem of Maths of your level.
okay i think i got this so the next one is -12d+3+14d+18 i got 2d+21 as the answer
you got this,. Congratulations. :)
yaaay i get it c: thank you so much i have been up all night worrying about this its 2 in the morning and i have been so nervous about htis but i got it c:
When you will get up, go through this post once again, just see what is the technique we are applying here, do some more problems related to it, you will be perfect by then. :)
i wrote it all as we went along im really eager to learn all of this
Great, it was nice talking as well as helping you.. you really interacted well, I appreciate you. :) Good Luck for Friday's test. :)
thank you so much i really do appreciate it you dont even know this helped me so much and im not so scared about failing my test this was the only thing i had problems with thank you goodnight from newyork c: <3
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