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\[\frac{ 4x-12 }{ x ^{2}-9 }\]
Ok, so 4x-12 = (3x + x) - (3 + 9), correct? And x^2 - 9 = (x+3)(x-3), do you understand this? So, now you have: (3x+x-3-9) / [ (x+3)(x-3) ] And this is equivalent of having: ( 3x-9 ) / (x+3)(x-3) + (x-3) / (x+3)(x-3) Which is: 3(x-3) / (x+3)(x-3) + (x-3) / (x+3)(x-3) = 3/ (x+3) + (x-3) / (x+3)(x-3) = 3/ (x+3) + 1 / (x+3) = 4/ (x+3)
@Diogo Okay thank you! i didn't know that you turn the numerator into (3x+x-3-9) But it makes sense now!
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