Question

Algebra 2-Polynomial Functions.......table attached :D

Answer 1

Found it.

Answer 2

Hey! You found it! lol

Answer 3

No idea. :3

Answer 4

Okay....thank you anyways

Answer 5

@ganeshie8 @Abhisar @johnweldon1993 @iambatman

Answer 6

thanks :D

Answer 7

@sleepyhead314

Answer 8

Oh god! Taking me back >.< lemme see If I can remember this lol

Answer 9

lol okay thanks!

Answer 10

mmm not linear cuz |f(-3)| does not equal |f(3)|
and not quadratic cuz f(-3) does not equal f(3)

Answer 11

okay thanks......how would we know about the other 2? :D

Answer 12

how about graph the points and figure out what it looks like? :P

Answer 13

Okay one second....I will try it out :D

Answer 14

*looks at the question again* ha, right... I failed Algebra 2...
umm... you might be better off having @johnweldon1993 figure it out for ya xD

Answer 15

Okay :D My laptop is freezing right now so it's being slow :/ I'm normally good at math but I don't get it :/

Answer 16

It just is a straight line......

Answer 17

nuh uh
not a straight line, that much I know
http://www.wolframalpha.com/input/?i=points+%28-6%2C+846%29%2C+%28-3%2C+108%29%2C+%280%2C0%29%2C+%283%2C-126%29%2C+%286%2C-918%29

Answer 18

If that were true then the differences would be the same as to stay linear

i.e the slope between 2 points on your table would equal the slope of 2 OTHER points on your table...and that is definitely not true here lol

It looks cubic to me from the points but I just need to figure out how lol

Answer 19

It looks like it but it could be wrong :/ i have no idea

Answer 20

Okay :D on my graph it looks straight

Answer 21

lol

Answer 22

http://www.wolframalpha.com/input/?i=points+%28-6%2C+846%29%2C+%28-3%2C+108%29%2C+%280%2C0%29%2C+%283%2C-126%29%2C+%286%2C-918%29

there are the graphed points for ya...

it does look cubic... but it is not like any cubic I know...
I want to say "none of the above" ... but idk

Answer 23

I will just go with cubic :D

Answer 24

thank you guys for all of your help!

Answer 25

It was correct :P thanks again!

Answer 26

k

glad we could help xD

... why am I even here?... *shuffles away*

Answer 27

lol

Answer 28

And want to know why? lol just took a bit to remember the difference table thing >.<

Answer 29

sure!

Answer 30

well I would like to xD
I usually avoid Alg2 topics like the plague

Answer 31

lol

Answer 32

I loved math last year and I still enjoy it :P My favorites are pre-alg/alg1/geometry

Answer 33

So basically we write down your table

Answer 34

okay

Answer 35

Sidebar...you love math now...wait until calc 4 >.< lol I'm having so much fun in it lol

Answer 36

lol I have calc sr year.......pre calc next year yippee!......not lol

Answer 37

I won't be in calc 4 I don't think :/

Answer 38

o-o ha... ha...
I've learned to love calc1 and am now onto calc2...
should probably brush up on my alg2

Answer 39

lol

Answer 40

so yes, table I wrote that down then got stuck
the vertex point thingy of the cubic is probably not at the origin

Answer 41

Okay but back to your table...so first thing is you need to make sure you have a constant difference in the x portion....each time x goes up by 3 here...so thats a green light to continue

What you do...is take each pair of y-values...and subtract them



Notice how I wrote "1st degree" above what I just did

What we are doing, is continuously taking the difference of the y-values we have...until all the differences are the same...weird I know, but it works

So for example here, if all those differences I wrote were say...100....we would know we have a 1ST degree polynomial

however, they are not the same...so we move on, and check if we have 2nd degree polynomial